8/(x+2)=16/(x-3)

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Solution for 8/(x+2)=16/(x-3) equation:



8/(x+2)=16/(x-3)
We move all terms to the left:
8/(x+2)-(16/(x-3))=0
Domain of the equation: (x+2)!=0
We move all terms containing x to the left, all other terms to the right
x!=-2
x∈R
Domain of the equation: (x-3))!=0
x∈R
We calculate fractions
8x/((x+2)*(x-3)))+(-(16*(x+2))/((x+2)*(x-3)))=0
We calculate terms in parentheses: -(16*(x+2))/((x+2)*(x-3))), so:
16*(x+2))/((x+2)*(x-3))
We multiply all the terms by the denominator
16*(x+2))
We multiply parentheses
16x+
We add all the numbers together, and all the variables
16x
Back to the equation:
-(16x)
We add all the numbers together, and all the variables
-16x+8x/((x+2)*(x-3)))+(=0
We multiply all the terms by the denominator
-16x*((x+2)*(x-3)))+(+8x=0
We add all the numbers together, and all the variables
8x-16x*((x+2)*(x-3)))+(=0

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