8/(t+3)=7/(9t+5)

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Solution for 8/(t+3)=7/(9t+5) equation: 



8/(t+3)=7/(9t+5)

We move all terms to the left:

8/(t+3)-(7/(9t+5))=0



Domain of the equation: (t+3)!=0

We move all terms containing t to the left, all other terms to the right

t!=-3

t∈R





Domain of the equation: (9t+5))!=0

t∈R



We calculate fractions


72t/((t+3)*(9t+5)))+(-(7*(t+3))/((t+3)*(9t+5)))=0



We calculate terms in parentheses: -(7*(t+3))/((t+3)*(9t+5))), so:

7*(t+3))/((t+3)*(9t+5))

We multiply all the terms by the denominator


7*(t+3))

We multiply parentheses

7t+

We add all the numbers together, and all the variables

7t

Back to the equation:

-(7t)



We add all the numbers together, and all the variables

-7t+72t/((t+3)*(9t+5)))+(=0

We multiply all the terms by the denominator


-7t*((t+3)*(9t+5)))+(+72t=0

We add all the numbers together, and all the variables

72t-7t*((t+3)*(9t+5)))+(=0

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