8/(3x-2)=3/(x+1)

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Solution for 8/(3x-2)=3/(x+1) equation: 



8/(3x-2)=3/(x+1)

We move all terms to the left:

8/(3x-2)-(3/(x+1))=0



Domain of the equation: (3x-2)!=0

We move all terms containing x to the left, all other terms to the right

3x!=2

x!=2/3

x!=2/3

x∈R





Domain of the equation: (x+1))!=0

x∈R



We calculate fractions


8x/((3x-2)*(x+1)))+(-(3*(3x-2))/((3x-2)*(x+1)))=0



We calculate terms in parentheses: -(3*(3x-2))/((3x-2)*(x+1))), so:

3*(3x-2))/((3x-2)*(x+1))

We multiply all the terms by the denominator


3*(3x-2))

We multiply parentheses

9x+

We add all the numbers together, and all the variables

9x

Back to the equation:

-(9x)



We add all the numbers together, and all the variables

-9x+8x/((3x-2)*(x+1)))+(=0

We multiply all the terms by the denominator


-9x*((3x-2)*(x+1)))+(+8x=0

We add all the numbers together, and all the variables

8x-9x*((3x-2)*(x+1)))+(=0

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