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8-x=3-(x-5)
We move all terms to the left:
8-x-(3-(x-5))=0
We add all the numbers together, and all the variables
-1x-(3-(x-5))+8=0
We calculate terms in parentheses: -(3-(x-5)), so:We get rid of parentheses
3-(x-5)
determiningTheFunctionDomain -(x-5)+3
We get rid of parentheses
-x+5+3
We add all the numbers together, and all the variables
-1x+8
Back to the equation:
-(-1x+8)
-1x+1x-8+8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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