8-d(d+4)=3d-d(d+2)

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Solution for 8-d(d+4)=3d-d(d+2) equation:



8-d(d+4)=3d-d(d+2)
We move all terms to the left:
8-d(d+4)-(3d-d(d+2))=0
We multiply parentheses
-d^2-4d-(3d-d(d+2))+8=0
We calculate terms in parentheses: -(3d-d(d+2)), so:
3d-d(d+2)
We multiply parentheses
-d^2+3d-2d
We add all the numbers together, and all the variables
-1d^2+d
Back to the equation:
-(-1d^2+d)
We add all the numbers together, and all the variables
-1d^2-(-1d^2+d)-4d+8=0
We get rid of parentheses
-1d^2+1d^2-d-4d+8=0
We add all the numbers together, and all the variables
-5d+8=0
We move all terms containing d to the left, all other terms to the right
-5d=-8
d=-8/-5
d=1+3/5

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