8-7/8h=6-1/5h

Solution for 8-7/8h=6-1/5h equation:

8-7/8h=6-1/5h

We move all terms to the left:

8-7/8h-(6-1/5h)=0


Domain of the equation: 8h!=0

h!=0/8

h!=0

h∈R



Domain of the equation: 5h)!=0

h!=0/1

h!=0

h∈R


We add all the numbers together, and all the variables

-7/8h-(-1/5h+6)+8=0

We get rid of parentheses

-7/8h+1/5h-6+8=0

We calculate fractions


(-35h)/40h^2+8h/40h^2-6+8=0

We add all the numbers together, and all the variables

(-35h)/40h^2+8h/40h^2+2=0

We multiply all the terms by the denominator


(-35h)+8h+2*40h^2=0

We add all the numbers together, and all the variables

8h+(-35h)+2*40h^2=0

Wy multiply elements

80h^2+8h+(-35h)=0

We get rid of parentheses

80h^2+8h-35h=0

We add all the numbers together, and all the variables

80h^2-27h=0

a = 80; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·80·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*80}=\frac{0}{160}
=0
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*80}=\frac{54}{160}
=27/80
$