8-7(4x-2)=28x+6

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Solution for 8-7(4x-2)=28x+6 equation: 



8-7(4x-2)=28x+6

We move all terms to the left:

8-7(4x-2)-(28x+6)=0

We multiply parentheses

-28x-(28x+6)+14+8=0

We get rid of parentheses

-28x-28x-6+14+8=0

We add all the numbers together, and all the variables

-56x+16=0

We move all terms containing x to the left, all other terms to the right

-56x=-16

x=-16/-56

x=2/7

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