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8-6x^2=1
We move all terms to the left:
8-6x^2-(1)=0
We add all the numbers together, and all the variables
-6x^2+7=0
a = -6; b = 0; c = +7;
Δ = b2-4ac
Δ = 02-4·(-6)·7
Δ = 168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{168}=\sqrt{4*42}=\sqrt{4}*\sqrt{42}=2\sqrt{42}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{42}}{2*-6}=\frac{0-2\sqrt{42}}{-12} =-\frac{2\sqrt{42}}{-12} =-\frac{\sqrt{42}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{42}}{2*-6}=\frac{0+2\sqrt{42}}{-12} =\frac{2\sqrt{42}}{-12} =\frac{\sqrt{42}}{-6} $
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