8-5(2x+3)=2(x-4)

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Solution for 8-5(2x+3)=2(x-4) equation: 



8-5(2x+3)=2(x-4)

We move all terms to the left:

8-5(2x+3)-(2(x-4))=0

We multiply parentheses

-10x-(2(x-4))-15+8=0



We calculate terms in parentheses: -(2(x-4)), so:

2(x-4)

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We add all the numbers together, and all the variables

-10x-(2x-8)-7=0

We get rid of parentheses

-10x-2x+8-7=0

We add all the numbers together, and all the variables

-12x+1=0

We move all terms containing x to the left, all other terms to the right

-12x=-1

x=-1/-12

x=1/12

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