8-4c=3(c+12)

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Solution for 8-4c=3(c+12) equation: 



8-4c=3(c+12)

We move all terms to the left:

8-4c-(3(c+12))=0



We calculate terms in parentheses: -(3(c+12)), so:

3(c+12)

We multiply parentheses

3c+36

Back to the equation:

-(3c+36)



We get rid of parentheses

-4c-3c-36+8=0

We add all the numbers together, and all the variables

-7c-28=0

We move all terms containing c to the left, all other terms to the right

-7c=28

c=28/-7

c=-4

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