8-4(x-5)=-2(3x-2)

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Solution for 8-4(x-5)=-2(3x-2) equation: 



8-4(x-5)=-2(3x-2)

We move all terms to the left:

8-4(x-5)-(-2(3x-2))=0

We multiply parentheses

-4x-(-2(3x-2))+20+8=0



We calculate terms in parentheses: -(-2(3x-2)), so:

-2(3x-2)

We multiply parentheses

-6x+4

Back to the equation:

-(-6x+4)



We add all the numbers together, and all the variables

-4x-(-6x+4)+28=0

We get rid of parentheses

-4x+6x-4+28=0

We add all the numbers together, and all the variables

2x+24=0

We move all terms containing x to the left, all other terms to the right

2x=-24

x=-24/2

x=-12

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