8-3*(j-7)=-3(2-j)-j

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Solution for 8-3*(j-7)=-3(2-j)-j equation: 



8-3(j-7)=-3(2-j)-j

We move all terms to the left:

8-3(j-7)-(-3(2-j)-j)=0

We add all the numbers together, and all the variables

-3(j-7)-(-3(-1j+2)-j)+8=0

We multiply parentheses

-3j-(-3(-1j+2)-j)+21+8=0



We calculate terms in parentheses: -(-3(-1j+2)-j), so:

-3(-1j+2)-j

We add all the numbers together, and all the variables

-1j-3(-1j+2)

We multiply parentheses

-1j+3j-6

We add all the numbers together, and all the variables

2j-6

Back to the equation:

-(2j-6)



We add all the numbers together, and all the variables

-3j-(2j-6)+29=0

We get rid of parentheses

-3j-2j+6+29=0

We add all the numbers together, and all the variables

-5j+35=0

We move all terms containing j to the left, all other terms to the right

-5j=-35

j=-35/-5

j=+7

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