8-3(x+1)=2(x+5)

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Solution for 8-3(x+1)=2(x+5) equation: 



8-3(x+1)=2(x+5)

We move all terms to the left:

8-3(x+1)-(2(x+5))=0

We multiply parentheses

-3x-(2(x+5))-3+8=0



We calculate terms in parentheses: -(2(x+5)), so:

2(x+5)

We multiply parentheses

2x+10

Back to the equation:

-(2x+10)



We add all the numbers together, and all the variables

-3x-(2x+10)+5=0

We get rid of parentheses

-3x-2x-10+5=0

We add all the numbers together, and all the variables

-5x-5=0

We move all terms containing x to the left, all other terms to the right

-5x=5

x=5/-5

x=-1

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