8-3(2y+7)=5(3y-4)-14

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Solution for 8-3(2y+7)=5(3y-4)-14 equation: 



8-3(2y+7)=5(3y-4)-14

We move all terms to the left:

8-3(2y+7)-(5(3y-4)-14)=0

We multiply parentheses

-6y-(5(3y-4)-14)-21+8=0



We calculate terms in parentheses: -(5(3y-4)-14), so:

5(3y-4)-14

We multiply parentheses

15y-20-14

We add all the numbers together, and all the variables

15y-34

Back to the equation:

-(15y-34)



We add all the numbers together, and all the variables

-6y-(15y-34)-13=0

We get rid of parentheses

-6y-15y+34-13=0

We add all the numbers together, and all the variables

-21y+21=0

We move all terms containing y to the left, all other terms to the right

-21y=-21

y=-21/-21

y=1

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