8-3(2x-5)=4(x+3)

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Solution for 8-3(2x-5)=4(x+3) equation:



8-3(2x-5)=4(x+3)
We move all terms to the left:
8-3(2x-5)-(4(x+3))=0
We multiply parentheses
-6x-(4(x+3))+15+8=0
We calculate terms in parentheses: -(4(x+3)), so:
4(x+3)
We multiply parentheses
4x+12
Back to the equation:
-(4x+12)
We add all the numbers together, and all the variables
-6x-(4x+12)+23=0
We get rid of parentheses
-6x-4x-12+23=0
We add all the numbers together, and all the variables
-10x+11=0
We move all terms containing x to the left, all other terms to the right
-10x=-11
x=-11/-10
x=1+1/10

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