8-3(2x-5)=4(x+2)

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Solution for 8-3(2x-5)=4(x+2) equation: 



8-3(2x-5)=4(x+2)

We move all terms to the left:

8-3(2x-5)-(4(x+2))=0

We multiply parentheses

-6x-(4(x+2))+15+8=0



We calculate terms in parentheses: -(4(x+2)), so:

4(x+2)

We multiply parentheses

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

-6x-(4x+8)+23=0

We get rid of parentheses

-6x-4x-8+23=0

We add all the numbers together, and all the variables

-10x+15=0

We move all terms containing x to the left, all other terms to the right

-10x=-15

x=-15/-10

x=1+1/2

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