8-3(2n+4)=4(n+5)+2n

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Solution for 8-3(2n+4)=4(n+5)+2n equation: 



8-3(2n+4)=4(n+5)+2n

We move all terms to the left:

8-3(2n+4)-(4(n+5)+2n)=0

We multiply parentheses

-6n-(4(n+5)+2n)-12+8=0



We calculate terms in parentheses: -(4(n+5)+2n), so:

4(n+5)+2n

We add all the numbers together, and all the variables

2n+4(n+5)

We multiply parentheses

2n+4n+20

We add all the numbers together, and all the variables

6n+20

Back to the equation:

-(6n+20)



We add all the numbers together, and all the variables

-6n-(6n+20)-4=0

We get rid of parentheses

-6n-6n-20-4=0

We add all the numbers together, and all the variables

-12n-24=0

We move all terms containing n to the left, all other terms to the right

-12n=24

n=24/-12

n=-2

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