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8-2m(m+7)=5m-12
We move all terms to the left:
8-2m(m+7)-(5m-12)=0
We multiply parentheses
-2m^2-14m-(5m-12)+8=0
We get rid of parentheses
-2m^2-14m-5m+12+8=0
We add all the numbers together, and all the variables
-2m^2-19m+20=0
a = -2; b = -19; c = +20;
Δ = b2-4ac
Δ = -192-4·(-2)·20
Δ = 521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{521}}{2*-2}=\frac{19-\sqrt{521}}{-4} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{521}}{2*-2}=\frac{19+\sqrt{521}}{-4} $
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