8-2(x+1)=5(x-1)

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Solution for 8-2(x+1)=5(x-1) equation: 



8-2(x+1)=5(x-1)

We move all terms to the left:

8-2(x+1)-(5(x-1))=0

We multiply parentheses

-2x-(5(x-1))-2+8=0



We calculate terms in parentheses: -(5(x-1)), so:

5(x-1)

We multiply parentheses

5x-5

Back to the equation:

-(5x-5)



We add all the numbers together, and all the variables

-2x-(5x-5)+6=0

We get rid of parentheses

-2x-5x+5+6=0

We add all the numbers together, and all the variables

-7x+11=0

We move all terms containing x to the left, all other terms to the right

-7x=-11

x=-11/-7

x=1+4/7

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