8-2(d-4)=3(5-d)+12

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Solution for 8-2(d-4)=3(5-d)+12 equation: 



8-2(d-4)=3(5-d)+12

We move all terms to the left:

8-2(d-4)-(3(5-d)+12)=0

We add all the numbers together, and all the variables

-2(d-4)-(3(-1d+5)+12)+8=0

We multiply parentheses

-2d-(3(-1d+5)+12)+8+8=0



We calculate terms in parentheses: -(3(-1d+5)+12), so:

3(-1d+5)+12

We multiply parentheses

-3d+15+12

We add all the numbers together, and all the variables

-3d+27

Back to the equation:

-(-3d+27)



We add all the numbers together, and all the variables

-2d-(-3d+27)+16=0

We get rid of parentheses

-2d+3d-27+16=0

We add all the numbers together, and all the variables

d-11=0

We move all terms containing d to the left, all other terms to the right

d=11

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