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8-2(3-x)=4x-2(x+1
We move all terms to the left:
8-2(3-x)-(4x-2(x+1)=0
We add all the numbers together, and all the variables
-2(-1x+3)-(4x-2(x+1)+8=0
We multiply parentheses
2x-(4x-2(x+1)+8-6=0
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