8-2(1-x)=7-2(2-3x)-2x

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Solution for 8-2(1-x)=7-2(2-3x)-2x equation:



8-2(1-x)=7-2(2-3x)-2x
We move all terms to the left:
8-2(1-x)-(7-2(2-3x)-2x)=0
We add all the numbers together, and all the variables
-2(-1x+1)-(7-2(-3x+2)-2x)+8=0
We multiply parentheses
2x-(7-2(-3x+2)-2x)-2+8=0
We calculate terms in parentheses: -(7-2(-3x+2)-2x), so:
7-2(-3x+2)-2x
determiningTheFunctionDomain -2(-3x+2)-2x+7
We add all the numbers together, and all the variables
-2x-2(-3x+2)+7
We multiply parentheses
-2x+6x-4+7
We add all the numbers together, and all the variables
4x+3
Back to the equation:
-(4x+3)
We add all the numbers together, and all the variables
2x-(4x+3)+6=0
We get rid of parentheses
2x-4x-3+6=0
We add all the numbers together, and all the variables
-2x+3=0
We move all terms containing x to the left, all other terms to the right
-2x=-3
x=-3/-2
x=1+1/2

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