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8-1/4p=-1/2p
We move all terms to the left:
8-1/4p-(-1/2p)=0
Domain of the equation: 4p!=0
p!=0/4
p!=0
p∈R
Domain of the equation: 2p)!=0We get rid of parentheses
p!=0/1
p!=0
p∈R
-1/4p+1/2p+8=0
We calculate fractions
(-2p)/8p^2+4p/8p^2+8=0
We multiply all the terms by the denominator
(-2p)+4p+8*8p^2=0
We add all the numbers together, and all the variables
4p+(-2p)+8*8p^2=0
Wy multiply elements
64p^2+4p+(-2p)=0
We get rid of parentheses
64p^2+4p-2p=0
We add all the numbers together, and all the variables
64p^2+2p=0
a = 64; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·64·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*64}=\frac{-4}{128} =-1/32 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*64}=\frac{0}{128} =0 $
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