8-(x+3)=6-4(x-1)

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Solution for 8-(x+3)=6-4(x-1) equation: 



8-(x+3)=6-4(x-1)

We move all terms to the left:

8-(x+3)-(6-4(x-1))=0

We get rid of parentheses

-x-(6-4(x-1))-3+8=0



We calculate terms in parentheses: -(6-4(x-1)), so:

6-4(x-1)

determiningTheFunctionDomain
-4(x-1)+6

We multiply parentheses

-4x+4+6

We add all the numbers together, and all the variables

-4x+10

Back to the equation:

-(-4x+10)



We add all the numbers together, and all the variables

-1x-(-4x+10)+5=0

We get rid of parentheses

-1x+4x-10+5=0

We add all the numbers together, and all the variables

3x-5=0

We move all terms containing x to the left, all other terms to the right

3x=5

x=5/3

x=1+2/3

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