8-(3+b)=1(b-9)

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Solution for 8-(3+b)=1(b-9) equation:


Simplifying
8 + -1(3 + b) = 1(b + -9)
8 + (3 * -1 + b * -1) = 1(b + -9)
8 + (-3 + -1b) = 1(b + -9)

Combine like terms: 8 + -3 = 5
5 + -1b = 1(b + -9)

Reorder the terms:
5 + -1b = 1(-9 + b)
5 + -1b = (-9 * 1 + b * 1)
5 + -1b = (-9 + 1b)

Solving
5 + -1b = -9 + 1b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1b' to each side of the equation.
5 + -1b + -1b = -9 + 1b + -1b

Combine like terms: -1b + -1b = -2b
5 + -2b = -9 + 1b + -1b

Combine like terms: 1b + -1b = 0
5 + -2b = -9 + 0
5 + -2b = -9

Add '-5' to each side of the equation.
5 + -5 + -2b = -9 + -5

Combine like terms: 5 + -5 = 0
0 + -2b = -9 + -5
-2b = -9 + -5

Combine like terms: -9 + -5 = -14
-2b = -14

Divide each side by '-2'.
b = 7

Simplifying
b = 7

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