8-(2x-5)=6(3-x)-57

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Solution for 8-(2x-5)=6(3-x)-57 equation: 



8-(2x-5)=6(3-x)-57

We move all terms to the left:

8-(2x-5)-(6(3-x)-57)=0

We add all the numbers together, and all the variables

-(2x-5)-(6(-1x+3)-57)+8=0

We get rid of parentheses

-2x-(6(-1x+3)-57)+5+8=0



We calculate terms in parentheses: -(6(-1x+3)-57), so:

6(-1x+3)-57

We multiply parentheses

-6x+18-57

We add all the numbers together, and all the variables

-6x-39

Back to the equation:

-(-6x-39)



We add all the numbers together, and all the variables

-2x-(-6x-39)+13=0

We get rid of parentheses

-2x+6x+39+13=0

We add all the numbers together, and all the variables

4x+52=0

We move all terms containing x to the left, all other terms to the right

4x=-52

x=-52/4

x=-13

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