8+5(3n-4)=7(n-12)

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Solution for 8+5(3n-4)=7(n-12) equation: 



8+5(3n-4)=7(n-12)

We move all terms to the left:

8+5(3n-4)-(7(n-12))=0

We multiply parentheses

15n-(7(n-12))-20+8=0



We calculate terms in parentheses: -(7(n-12)), so:

7(n-12)

We multiply parentheses

7n-84

Back to the equation:

-(7n-84)



We add all the numbers together, and all the variables

15n-(7n-84)-12=0

We get rid of parentheses

15n-7n+84-12=0

We add all the numbers together, and all the variables

8n+72=0

We move all terms containing n to the left, all other terms to the right

8n=-72

n=-72/8

n=-9

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