8+4x=2x+8+2x2x+52x+8

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Solution for 8+4x=2x+8+2x2x+52x+8 equation: 



8+4x=2x+8+2x^2x+52x+8

We move all terms to the left:

8+4x-(2x+8+2x^2x+52x+8)=0

We get rid of parentheses

-2x^2x-2x-52x+4x-8-8+8=0

We add all the numbers together, and all the variables

-2x^2x-50x-8=0

We move all terms containing x to the left, all other terms to the right

-2x^2x-50x=8

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