8+4(4x-5)=9-3(2x+1)

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Solution for 8+4(4x-5)=9-3(2x+1) equation: 



8+4(4x-5)=9-3(2x+1)

We move all terms to the left:

8+4(4x-5)-(9-3(2x+1))=0

We multiply parentheses

16x-(9-3(2x+1))-20+8=0



We calculate terms in parentheses: -(9-3(2x+1)), so:

9-3(2x+1)

determiningTheFunctionDomain
-3(2x+1)+9

We multiply parentheses

-6x-3+9

We add all the numbers together, and all the variables

-6x+6

Back to the equation:

-(-6x+6)



We add all the numbers together, and all the variables

16x-(-6x+6)-12=0

We get rid of parentheses

16x+6x-6-12=0

We add all the numbers together, and all the variables

22x-18=0

We move all terms containing x to the left, all other terms to the right

22x=18

x=18/22

x=9/11

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