8+4(2u-1)=-2(7u-7)+7u

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Solution for 8+4(2u-1)=-2(7u-7)+7u equation: 



8+4(2u-1)=-2(7u-7)+7u

We move all terms to the left:

8+4(2u-1)-(-2(7u-7)+7u)=0

We multiply parentheses

8u-(-2(7u-7)+7u)-4+8=0



We calculate terms in parentheses: -(-2(7u-7)+7u), so:

-2(7u-7)+7u

We add all the numbers together, and all the variables

7u-2(7u-7)

We multiply parentheses

7u-14u+14

We add all the numbers together, and all the variables

-7u+14

Back to the equation:

-(-7u+14)



We add all the numbers together, and all the variables

8u-(-7u+14)+4=0

We get rid of parentheses

8u+7u-14+4=0

We add all the numbers together, and all the variables

15u-10=0

We move all terms containing u to the left, all other terms to the right

15u=10

u=10/15

u=2/3

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