8+4(-6+x)=12x-2(x-4)

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Solution for 8+4(-6+x)=12x-2(x-4) equation: 



8+4(-6+x)=12x-2(x-4)

We move all terms to the left:

8+4(-6+x)-(12x-2(x-4))=0

We add all the numbers together, and all the variables

4(x-6)-(12x-2(x-4))+8=0

We multiply parentheses

4x-(12x-2(x-4))-24+8=0



We calculate terms in parentheses: -(12x-2(x-4)), so:

12x-2(x-4)

We multiply parentheses

12x-2x+8

We add all the numbers together, and all the variables

10x+8

Back to the equation:

-(10x+8)



We add all the numbers together, and all the variables

4x-(10x+8)-16=0

We get rid of parentheses

4x-10x-8-16=0

We add all the numbers together, and all the variables

-6x-24=0

We move all terms containing x to the left, all other terms to the right

-6x=24

x=24/-6

x=-4

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