8+3/7x=x

Solution for 8+3/7x=x equation:

8+3/7x=x

We move all terms to the left:

8+3/7x-(x)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R


We add all the numbers together, and all the variables

-1x+3/7x+8=0

We multiply all the terms by the denominator


-1x*7x+8*7x+3=0

Wy multiply elements

-7x^2+56x+3=0

a = -7; b = 56; c = +3;
Δ = b2-4ac
Δ = 562-4·(-7)·3
Δ = 3220
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3220}=\sqrt{4*805}=\sqrt{4}*\sqrt{805}=2\sqrt{805}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-2\sqrt{805}}{2*-7}=\frac{-56-2\sqrt{805}}{-14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+2\sqrt{805}}{2*-7}=\frac{-56+2\sqrt{805}}{-14}
$