8+3(4x-4)=9-4(2x+1)

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Solution for 8+3(4x-4)=9-4(2x+1) equation: 



8+3(4x-4)=9-4(2x+1)

We move all terms to the left:

8+3(4x-4)-(9-4(2x+1))=0

We multiply parentheses

12x-(9-4(2x+1))-12+8=0



We calculate terms in parentheses: -(9-4(2x+1)), so:

9-4(2x+1)

determiningTheFunctionDomain
-4(2x+1)+9

We multiply parentheses

-8x-4+9

We add all the numbers together, and all the variables

-8x+5

Back to the equation:

-(-8x+5)



We add all the numbers together, and all the variables

12x-(-8x+5)-4=0

We get rid of parentheses

12x+8x-5-4=0

We add all the numbers together, and all the variables

20x-9=0

We move all terms containing x to the left, all other terms to the right

20x=9

x=9/20

x=9/20

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