8+2x-(6x-3)=4(3-x)-1

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Solution for 8+2x-(6x-3)=4(3-x)-1 equation: 



8+2x-(6x-3)=4(3-x)-1

We move all terms to the left:

8+2x-(6x-3)-(4(3-x)-1)=0

We add all the numbers together, and all the variables

2x-(6x-3)-(4(-1x+3)-1)+8=0

We get rid of parentheses

2x-6x-(4(-1x+3)-1)+3+8=0



We calculate terms in parentheses: -(4(-1x+3)-1), so:

4(-1x+3)-1

We multiply parentheses

-4x+12-1

We add all the numbers together, and all the variables

-4x+11

Back to the equation:

-(-4x+11)



We add all the numbers together, and all the variables

-4x-(-4x+11)+11=0

We get rid of parentheses

-4x+4x-11+11=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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