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8+2(x-3)=x-5
We move all terms to the left:
8+2(x-3)-(x-5)=0
We multiply parentheses
2x-(x-5)-6+8=0
We get rid of parentheses
2x-x+5-6+8=0
We add all the numbers together, and all the variables
x+7=0
We move all terms containing x to the left, all other terms to the right
x=-7
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