8+2(7u-1)=-2(2u-6)+6u

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Solution for 8+2(7u-1)=-2(2u-6)+6u equation: 



8+2(7u-1)=-2(2u-6)+6u

We move all terms to the left:

8+2(7u-1)-(-2(2u-6)+6u)=0

We multiply parentheses

14u-(-2(2u-6)+6u)-2+8=0



We calculate terms in parentheses: -(-2(2u-6)+6u), so:

-2(2u-6)+6u

We add all the numbers together, and all the variables

6u-2(2u-6)

We multiply parentheses

6u-4u+12

We add all the numbers together, and all the variables

2u+12

Back to the equation:

-(2u+12)



We add all the numbers together, and all the variables

14u-(2u+12)+6=0

We get rid of parentheses

14u-2u-12+6=0

We add all the numbers together, and all the variables

12u-6=0

We move all terms containing u to the left, all other terms to the right

12u=6

u=6/12

u=1/2

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