8+2(2x-3)=6-(x-4)

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Solution for 8+2(2x-3)=6-(x-4) equation: 



8+2(2x-3)=6-(x-4)

We move all terms to the left:

8+2(2x-3)-(6-(x-4))=0

We multiply parentheses

4x-(6-(x-4))-6+8=0



We calculate terms in parentheses: -(6-(x-4)), so:

6-(x-4)

determiningTheFunctionDomain
-(x-4)+6

We get rid of parentheses

-x+4+6

We add all the numbers together, and all the variables

-1x+10

Back to the equation:

-(-1x+10)



We add all the numbers together, and all the variables

4x-(-1x+10)+2=0

We get rid of parentheses

4x+1x-10+2=0

We add all the numbers together, and all the variables

5x-8=0

We move all terms containing x to the left, all other terms to the right

5x=8

x=8/5

x=1+3/5

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