8+2(2u-1)=-4(2u-3)+2u

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Solution for 8+2(2u-1)=-4(2u-3)+2u equation: 



8+2(2u-1)=-4(2u-3)+2u

We move all terms to the left:

8+2(2u-1)-(-4(2u-3)+2u)=0

We multiply parentheses

4u-(-4(2u-3)+2u)-2+8=0



We calculate terms in parentheses: -(-4(2u-3)+2u), so:

-4(2u-3)+2u

We add all the numbers together, and all the variables

2u-4(2u-3)

We multiply parentheses

2u-8u+12

We add all the numbers together, and all the variables

-6u+12

Back to the equation:

-(-6u+12)



We add all the numbers together, and all the variables

4u-(-6u+12)+6=0

We get rid of parentheses

4u+6u-12+6=0

We add all the numbers together, and all the variables

10u-6=0

We move all terms containing u to the left, all other terms to the right

10u=6

u=6/10

u=3/5

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