8+12a-10a=3(a+4)+2(-a-9)

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Solution for 8+12a-10a=3(a+4)+2(-a-9) equation: 



8+12a-10a=3(a+4)+2(-a-9)

We move all terms to the left:

8+12a-10a-(3(a+4)+2(-a-9))=0

We add all the numbers together, and all the variables

12a-10a-(3(a+4)+2(-1a-9))+8=0

We add all the numbers together, and all the variables

2a-(3(a+4)+2(-1a-9))+8=0



We calculate terms in parentheses: -(3(a+4)+2(-1a-9)), so:

3(a+4)+2(-1a-9)

We multiply parentheses

3a-2a+12-18

We add all the numbers together, and all the variables

a-6

Back to the equation:

-(a-6)



We get rid of parentheses

2a-a+6+8=0

We add all the numbers together, and all the variables

a+14=0

We move all terms containing a to the left, all other terms to the right

a=-14

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