8+(34/7)x-9=x+8

Solution for 8+(34/7)x-9=x+8 equation:

8+(34/7)x-9=x+8

We move all terms to the left:

8+(34/7)x-9-(x+8)=0


Domain of the equation: 7)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+34/7)x-(x+8)+8-9=0

We add all the numbers together, and all the variables

(+34/7)x-(x+8)-1=0

We multiply parentheses

34x^2-(x+8)-1=0

We get rid of parentheses

34x^2-x-8-1=0

We add all the numbers together, and all the variables

34x^2-1x-9=0

a = 34; b = -1; c = -9;
Δ = b2-4ac
Δ = -12-4·34·(-9)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-35}{2*34}=\frac{-34}{68}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+35}{2*34}=\frac{36}{68}
=9/17
$