8+(1/5)b=(3/10)b

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Solution for 8+(1/5)b=(3/10)b equation:



8+(1/5)b=(3/10)b
We move all terms to the left:
8+(1/5)b-((3/10)b)=0
Domain of the equation: 5)b!=0
b!=0/1
b!=0
b∈R
Domain of the equation: 10)b)!=0
b!=0/1
b!=0
b∈R
We add all the numbers together, and all the variables
(+1/5)b-((+3/10)b)+8=0
We multiply parentheses
b^2-((+3/10)b)+8=0
We multiply all the terms by the denominator
b^2*10)b)-((+8*10)b)+3=0
We add all the numbers together, and all the variables
b^2*10)b)-(80b)+3=0
We add all the numbers together, and all the variables
b^2*10)b)-80b+3=0
Wy multiply elements
10b^3=0
We do not support ebpression: b^3

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