8*(1x-2)=3*(2+1x)

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Solution for 8*(1x-2)=3*(2+1x) equation: 



8(1x-2)=3(2+1x)

We move all terms to the left:

8(1x-2)-(3(2+1x))=0

We add all the numbers together, and all the variables

8(x-2)-(3(x+2))=0

We multiply parentheses

8x-(3(x+2))-16=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

8x-3x-6-16=0

We add all the numbers together, and all the variables

5x-22=0

We move all terms containing x to the left, all other terms to the right

5x=22

x=22/5

x=4+2/5

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