8(z-5)-7(3z-2)=1-10z

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Solution for 8(z-5)-7(3z-2)=1-10z equation: 



8(z-5)-7(3z-2)=1-10z

We move all terms to the left:

8(z-5)-7(3z-2)-(1-10z)=0

We add all the numbers together, and all the variables

8(z-5)-7(3z-2)-(-10z+1)=0

We multiply parentheses

8z-21z-(-10z+1)-40+14=0

We get rid of parentheses

8z-21z+10z-1-40+14=0

We add all the numbers together, and all the variables

-3z-27=0

We move all terms containing z to the left, all other terms to the right

-3z=27

z=27/-3

z=-9

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