8(z-2)=4(2z-4)

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Solution for 8(z-2)=4(2z-4) equation:


Simplifying
8(z + -2) = 4(2z + -4)

Reorder the terms:
8(-2 + z) = 4(2z + -4)
(-2 * 8 + z * 8) = 4(2z + -4)
(-16 + 8z) = 4(2z + -4)

Reorder the terms:
-16 + 8z = 4(-4 + 2z)
-16 + 8z = (-4 * 4 + 2z * 4)
-16 + 8z = (-16 + 8z)

Add '16' to each side of the equation.
-16 + 16 + 8z = -16 + 16 + 8z

Combine like terms: -16 + 16 = 0
0 + 8z = -16 + 16 + 8z
8z = -16 + 16 + 8z

Combine like terms: -16 + 16 = 0
8z = 0 + 8z
8z = 8z

Add '-8z' to each side of the equation.
8z + -8z = 8z + -8z

Combine like terms: 8z + -8z = 0
0 = 8z + -8z

Combine like terms: 8z + -8z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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