8(z+8)=7(z-5)+z

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Solution for 8(z+8)=7(z-5)+z equation: 



8(z+8)=7(z-5)+z

We move all terms to the left:

8(z+8)-(7(z-5)+z)=0

We multiply parentheses

8z-(7(z-5)+z)+64=0



We calculate terms in parentheses: -(7(z-5)+z), so:

7(z-5)+z

We add all the numbers together, and all the variables

z+7(z-5)

We multiply parentheses

z+7z-35

We add all the numbers together, and all the variables

8z-35

Back to the equation:

-(8z-35)



We get rid of parentheses

8z-8z+35+64=0

We add all the numbers together, and all the variables

99!=0

There is no solution for this equation

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