8(z+4)-7(z+4)=13

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Solution for 8(z+4)-7(z+4)=13 equation:


Simplifying
8(z + 4) + -7(z + 4) = 13

Reorder the terms:
8(4 + z) + -7(z + 4) = 13
(4 * 8 + z * 8) + -7(z + 4) = 13
(32 + 8z) + -7(z + 4) = 13

Reorder the terms:
32 + 8z + -7(4 + z) = 13
32 + 8z + (4 * -7 + z * -7) = 13
32 + 8z + (-28 + -7z) = 13

Reorder the terms:
32 + -28 + 8z + -7z = 13

Combine like terms: 32 + -28 = 4
4 + 8z + -7z = 13

Combine like terms: 8z + -7z = 1z
4 + 1z = 13

Solving
4 + 1z = 13

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 1z = 13 + -4

Combine like terms: 4 + -4 = 0
0 + 1z = 13 + -4
1z = 13 + -4

Combine like terms: 13 + -4 = 9
1z = 9

Divide each side by '1'.
z = 9

Simplifying
z = 9

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