8(z+4)-2(z-2)=3(z-1)+2(z-3)

Solution for 8(z+4)-2(z-2)=3(z-1)+2(z-3) equation:

8(z+4)-2(z-2)=3(z-1)+2(z-3)

We move all terms to the left:

8(z+4)-2(z-2)-(3(z-1)+2(z-3))=0

We multiply parentheses

8z-2z-(3(z-1)+2(z-3))+32+4=0


We calculate terms in parentheses: -(3(z-1)+2(z-3)), so:

3(z-1)+2(z-3)

We multiply parentheses

3z+2z-3-6

We add all the numbers together, and all the variables

5z-9

Back to the equation:

-(5z-9)


We add all the numbers together, and all the variables

6z-(5z-9)+36=0

We get rid of parentheses

6z-5z+9+36=0

We add all the numbers together, and all the variables

z+45=0

We move all terms containing z to the left, all other terms to the right

z=-45