8(z+3)-3z=2(z+12)+3z

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Solution for 8(z+3)-3z=2(z+12)+3z equation: 


Simplifying
8(z + 3) + -3z = 2(z + 12) + 3z

Reorder the terms:
8(3 + z) + -3z = 2(z + 12) + 3z
(3 * 8 + z * 8) + -3z = 2(z + 12) + 3z
(24 + 8z) + -3z = 2(z + 12) + 3z

Combine like terms: 8z + -3z = 5z
24 + 5z = 2(z + 12) + 3z

Reorder the terms:
24 + 5z = 2(12 + z) + 3z
24 + 5z = (12 * 2 + z * 2) + 3z
24 + 5z = (24 + 2z) + 3z

Combine like terms: 2z + 3z = 5z
24 + 5z = 24 + 5z

Add '-24' to each side of the equation.
24 + -24 + 5z = 24 + -24 + 5z

Combine like terms: 24 + -24 = 0
0 + 5z = 24 + -24 + 5z
5z = 24 + -24 + 5z

Combine like terms: 24 + -24 = 0
5z = 0 + 5z
5z = 5z

Add '-5z' to each side of the equation.
5z + -5z = 5z + -5z

Combine like terms: 5z + -5z = 0
0 = 5z + -5z

Combine like terms: 5z + -5z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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