8(z+2)=3(z+1)-22

Solution for 8(z+2)=3(z+1)-22 equation:

8(z+2)=3(z+1)-22

We move all terms to the left:

8(z+2)-(3(z+1)-22)=0

We multiply parentheses

8z-(3(z+1)-22)+16=0


We calculate terms in parentheses: -(3(z+1)-22), so:

3(z+1)-22

We multiply parentheses

3z+3-22

We add all the numbers together, and all the variables

3z-19

Back to the equation:

-(3z-19)


We get rid of parentheses

8z-3z+19+16=0

We add all the numbers together, and all the variables

5z+35=0

We move all terms containing z to the left, all other terms to the right

5z=-35

z=-35/5

z=-7