8(z+1)-2(z-2)=3(z-2)+2(z-3)

Solution for 8(z+1)-2(z-2)=3(z-2)+2(z-3) equation:

8(z+1)-2(z-2)=3(z-2)+2(z-3)

We move all terms to the left:

8(z+1)-2(z-2)-(3(z-2)+2(z-3))=0

We multiply parentheses

8z-2z-(3(z-2)+2(z-3))+8+4=0


We calculate terms in parentheses: -(3(z-2)+2(z-3)), so:

3(z-2)+2(z-3)

We multiply parentheses

3z+2z-6-6

We add all the numbers together, and all the variables

5z-12

Back to the equation:

-(5z-12)


We add all the numbers together, and all the variables

6z-(5z-12)+12=0

We get rid of parentheses

6z-5z+12+12=0

We add all the numbers together, and all the variables

z+24=0

We move all terms containing z to the left, all other terms to the right

z=-24